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2011-10-17 答案 CD
对记录类型不能使用IS NOT NULL判断,否则会出现:
PLS-00306: wrong number or types of arguments in call to 'IS NOT NULL'
这导致AB出现异常。
Steven Feuerstein建议你采用D的做法以便于重用代码。
2011-10-18: TO_CHAR格式
作者: Steven Feuerstein
难度:中
我的经理叫我写一个函数,这个函数接受一个正整数并返回相应的序数(比如,2->2nd, 145->145th), 这个序数是一个字符串。这个函数只接受1和50,000之间的整数。
下列的哪些选项实现了函数plch_n_to_nth, 从而使得它满足上述需求,在下列块被执行之后:
BEGIN
DBMS_OUTPUT.put_line (plch_n_to_nth (1));
DBMS_OUTPUT.put_line (plch_n_to_nth (8));
DBMS_OUTPUT.put_line (plch_n_to_nth (256));
DBMS_OUTPUT.put_line (plch_n_to_nth (25763));
END;
/
我能见到如下输出:
1st
8th
256th
25763rd
英语序数词定义可参见:
http://en.wikipedia.org/wiki/English_numerals#Ordinal_numbers
(A)
CREATE OR REPLACE FUNCTION plch_n_to_nth (n_in IN INTEGER)
RETURN VARCHAR2
IS
BEGIN
RETURN TO_CHAR (n_in, '9999th');
END;
/
(B)
CREATE OR REPLACE FUNCTION plch_n_to_nth (n_in IN INTEGER)
RETURN VARCHAR2
IS
BEGIN
RETURN LOWER (
TO_CHAR (
TO_DATE ('1-1-' || n_in, 'dd-mm-yyyy')
, 'FMYYYYth'));
END;
/
(C)
CREATE OR REPLACE FUNCTION plch_n_to_nth (n_in IN INTEGER)
RETURN VARCHAR2
IS
BEGIN
RETURN LOWER (
TO_CHAR (
TO_DATE ('1-1-2011 ' || n_in
, 'dd-mm-yyyy SSSSS')
, 'FMSSSSSth'));
END;
/
(D)
CREATE OR REPLACE FUNCTION plch_n_to_nth (
n_in IN INTEGER)
RETURN VARCHAR2
IS
c_last_digit CONSTANT PLS_INTEGER
:= MOD (n_in, 10) ;
c_tens_digit CONSTANT CHAR (1)
:= SUBSTR ('0' || TO_CHAR (n_in), -2, 1) ;
BEGIN
RETURN TO_CHAR (n_in)
|| CASE
WHEN c_tens_digit = '1' THEN 'th'
WHEN c_last_digit = 1 THEN 'st'
WHEN c_last_digit = 2 THEN 'nd'
WHEN c_last_digit = 3 THEN 'rd'
ELSE 'th'
END;
END plch_n_to_nth;
/
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