新手求助struts+spring_hibernate [复制链接]

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发表于 2007-7-17 10:43:02 |显示全部楼层

用eclipse写的一个数据库插入的功能，吏终不能成功，请大家帮我看一下
applicationContext.xml如下:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE beans PUBLIC "-//SPRING//DTD BEAN//EN" "http://www.springframework.org/dtd/spring-beans.dtd">

<beans>
<bean id="sessionFactory"
class="org.springframework.orm.hibernate3.LocalSessionFactoryBean">
<property name="configLocation">
<value>WEB-INF/hibernate.cfg.xml</value>
</property>
</bean>
<bean id="addUser1" class="test.spring.InsertUser" autowire="byName">
</bean>
</beans>

hibernate.cfg.xml如下:
<?xml version='1.0' encoding='UTF-8'?>
<!DOCTYPE hibernate-configuration PUBLIC
      "-//Hibernate/Hibernate Configuration DTD 3.0//EN"
      "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">


<hibernate-configuration>

<session-factory>
<mapping resource="test/hibernate/User1.hbm.xml" />

</session-factory>

</hibernate-configuration>

User1.hbm.xml如下:
<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">

<hibernate-mapping>
<class name="test.hibernate.User1" table="user1" dynamic-update="false"
dynamic-insert="false">
      <id name="id" type="java.lang.Long">
         <column name="id" />
      </id>
      <property name="name" type="java.lang.String">
         <column name="name" length="100" />
      </property>
      <property name="school" type="java.lang.String">
         <column name="school" length="100" />
      </property>
</class>
</hibernate-mapping>

User1.java如下:
package test.hibernate;

/**
* User1 generated by MyEclipse - Hibernate Tools
*/

public class User1  implements java.io.Serializable {

// Fields

   /**
   *
   */
private static final long serialVersionUID = -7496479896490190687L;
private Long id;
   private String name;
   private String school;

// Constructors

/** default constructor */
public User1() {
}

/** minimal constructor */
public User1(Long id) {
      this.id = id;
}

/** full constructor */
public User1(Long id, String name, String school) {
      this.id = id;
      this.name = name;
      this.school = school;
}

// Property accessors

public Long getId() {
      return this.id;
}

public void setId(Long id) {
      this.id = id;
}

public String getName() {
      return this.name;
}

public void setName(String name) {
      this.name = name;
}

public String getSchool() {
      return this.school;
}

public void setSchool(String school) {
      this.school = school;
}

}

Useraction如下:
/*
* Generated by MyEclipse Struts
* Template path: templates/java/JavaClass.vtl
*/
package test.struts.action;
import test.spring.impl.InsertUserImpl;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.struts.action.ActionForm;
import org.apache.struts.action.ActionForward;
import org.apache.struts.action.ActionMapping;
import test.spring.InsertUser;
import test.hibernate.User1;
/**
* MyEclipse Struts
* Creation date: 06-30-2007
*
* XDoclet definition:
* @struts.action validate="true"
*/
public class UserAction extends BaseAction {
/*
   * Generated Methods
   */

/**
   * Method execute
   * @param mapping
   * @param form
   * @param request
   * @param response
   * @return ActionForward
   */
public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response) {
try
{
InsertUserImpl ob =(InsertUser)getWebApplicationContext().getBean("addUser1"

;
User1 u=new User1();
long id=(long) 1.0;
u.setId(id);
u.setName("ddddd"

;
u.setSchool("dddd"

;
ob.add(u);
}
catch(Exception e)
{
System.out.print(e);
}

return mapping.findForward("ok"

;
}
}

InsertUser如下:
package test.spring;
import test.spring.impl.InsertUserImpl;
import test.hibernate.User1;
import org.springframework.orm.hibernate3.*;

public class InsertUser extends HibernateTemplate implements InsertUserImpl    {
public void add(User1 user) {
try
{
save(user);

}
catch(Exception e)
{
System.out.print("出你吗"+e);
}

}

public void del() {
// TODO 自动生成方法存根

}

public void disp() {
// TODO 自动生成方法存根

}

public void update() {
// TODO 自动生成方法存根

}

public void close(InsertUserImpl ob)
{

}
}

小弟有二个问题想问，
1.我这样来应用struts+spring+hibernate行不行，就是现在流行的用法是不是这样，我这样写有没有什么性能上的差别.
2.我UserAction后，并没有插入数据，而且sql查询器里好像这个表被占用一样，用select查询该表，就一直停在查询的状态，日志有警告信息：
Hibernate: insert into user1 (name, school, id) values (?, ?, ?)
2007-07-17 09:09:17,187 WARN  hibernate.util.JDBCExceptionReporter:48  -> SQL Warning: 0, SQLState:
2007-07-17 09:09:17,187 WARN  hibernate.util.JDBCExceptionReporter:49  -> [Microsoft][SQLServer 2000 Driver for JDBC]Database changed to beingo
2007-07-17 09:09:17,203 WARN  hibernate.util.JDBCExceptionReporter:48  -> SQL Warning: 0, SQLState:
2007-07-17 09:09:17,203 WARN  hibernate.util.JDBCExceptionReporter:49  -> [Microsoft][SQLServer 2000 Driver for JDBC][SQLServer]已将数据库上下文改为 'beingo'。
2007-07-17 09:09:17,203 WARN  hibernate.util.JDBCExceptionReporter:48  -> SQL Warning: 0, SQLState:
2007-07-17 09:09:17,203 WARN  hibernate.util.JDBCExceptionReporter:49  -> [Microsoft][SQLServer 2000 Driver for JDBC]Language changed to 简体中文
2007-07-17 09:09:17,203 WARN  hibernate.util.JDBCExceptionReporter:48  -> SQL Warning: 0, SQLState:
2007-07-17 09:09:17,203 WARN  hibernate.util.JDBCExceptionReporter:49  -> [Microsoft][SQLServer 2000 Driver for JDBC][SQLServer]已将语言设置改为简体中文。

请各位大哥大姐帮个忙

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